概要: , kBC= AC BC, kAC kBC=-1,即 x=1或x=2, 故所求点为C(1,0)或C(2,0).上一页 [1] [2] [3] [4] [5] [6]
, kBC=
AC
BC,
kAC kBC=-1,
即
x=1或x=2, 故所求点为C(1,0)或C(2,0).
上一页 [1] [2] [3] [4] [5] [6]
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